Simple Joule Thief Circuit - DIY Electronics Project

Published Sep 02, 2022
 2 hours to build
 Intermediate

In this Tutorial, We are Going To Make a Simple Joule Thief Circuit

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Components Used

BC547 TRANSISTORS
BC547 TRANSISTORS
1
Capacitor 220 pF
Multilayer Ceramic Capacitors MLCC - Leaded 250V 220pF C0G 10%
1
Resistor 22 kOhms
Metal Film Resistors - Through Hole 22K OHM 1/4W 1%
1
Resistor 330 Ohms
Metal Film Resistors - Through Hole FRN25 5% 330R
1
AA Battery
AA Battery
1
GPCB
PCBs & Breadboards PadBoard-3U 2 sided with plated holes
1
LED 5mm
LED 5mm
1
Wire
Hook-up Wire 788133 RED 100 FT
1
Description

Introduction

A joule thief circuit enables the battery to light an LED in the circuit even if that LED requires more battery power. For example, a 1.85V led can be lightened by a 1.5V battery cell through this circuit. Hence, it allows the dead battery cells to drive the LED loads. In short, the joule thief circuit is the voltage booster circuit that transforms the input voltage into a greater periodic voltage value. However, the circuit does not boost current. Since it steals energy or joules that's why named joules their circuit. But this small circuit is also known as a joule ringer, blocking oscillator, and vampire torch.

The joule thief circuit can be made using different methods. We are going to build this circuit with two transistor methods. Thus, the circuit requires very cheap components including transistors, coil, capacitors, and LED as its main elements. Also, it's easy to handle and simple to create.

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Hardware Components

Joule Thief Circuit

Working Explanation

The circuit operates by the 1.5V battery cells. A magnetic field developed around the coil because the current t passes through the wire's coil. As a result, it induces a greater amount of electricity in the coil, which is given to the base of transistor Q2 and opens the collector-emitter channel. The built-up energy of the circuit can't go through the transistor so it goes through the load, that is LED.

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